Math

by **Meika-Chan** Thu Oct 09 2008, 22:24

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Post n°51

Re: Math

Post by Meika-Chan Thu Oct 09 2008, 22:24

<<;

Solve for x:

2x^2+4x > x^2-x-6

I got x=-3, but I don't think that's right....

by **spyke543** Fri Oct 10 2008, 01:42

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Post n°52

Re: Math

Post by spyke543 Fri Oct 10 2008, 01:42

Actually

2(-3)² + 4(-3) = (-3)² - (-3) - 6

Lol.

by **quater** Fri Oct 10 2008, 16:17

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Post n°53

Re: Math

Post by quater Fri Oct 10 2008, 16:17

Oh nice.

Blood I thought you were in Calculus girl?

by **Aichu** Fri Oct 10 2008, 16:28

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Post n°54

Re: Math

Post by Aichu Fri Oct 10 2008, 16:28

Meika-Chan wrote:<<;

Solve for x:

2x^2+4x > x^2-x-6

I got x=-3, but I don't think that's right....

Jeepers creepers, you're only thirteen! Why are you doing such complex problems? Dazed

by **Meika-Chan** Fri Oct 10 2008, 16:30

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Post n°55

Re: Math

Post by Meika-Chan Fri Oct 10 2008, 16:30

quater wrote:Oh nice.

Blood I thought you were in Calculus girl?

that was last year, and I failed Cowboy

by **Meika-Chan** Fri Oct 10 2008, 16:30

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Post n°56

Re: Math

Post by Meika-Chan Fri Oct 10 2008, 16:30

spyke543 wrote:Actually

2(-3)² + 4(-3) = (-3)² - (-3) - 6

Lol.

<<; Multiply it out for me? D:

by **Meika-Chan** Fri Oct 10 2008, 16:31

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Post n°57

Re: Math

Post by Meika-Chan Fri Oct 10 2008, 16:31

Aichu wrote:

Meika-Chan wrote:<<;

Solve for x:

2x^2+4x > x^2-x-6

I got x=-3, but I don't think that's right....

Jeepers creepers, you're only thirteen! Why are you doing such complex problems?

I don't know Wahh

by **theBOSS.** Fri Oct 10 2008, 18:26

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Post n°58

Re: Math

Post by theBOSS. Fri Oct 10 2008, 18:26

I thought bloodly was 14 Dazed

If it's an inequality try isolating the variables, and factoring them

by **amaterasu** Fri Oct 10 2008, 19:29

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Post n°59

Re: Math

Post by amaterasu Fri Oct 10 2008, 19:29

Meika-Chan wrote:

Aichu wrote:

Meika-Chan wrote:<<;

Solve for x:

2x^2+4x > x^2-x-6

I got x=-3, but I don't think that's right....

Jeepers creepers, you're only thirteen! Why are you doing such complex problems?

I don't know

the> is just the same as =

by **amaterasu** Fri Oct 10 2008, 19:35

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Post n°60

Re: Math

Post by amaterasu Fri Oct 10 2008, 19:35

well check the formula and see if it is right

2x^2+4x > x^2-x-6
so 2(3)^2+4(3) > (3)^2-2-6
so 36+12 > 9-8
so 48 > 1

so you are right

by **Meika-Chan** Fri Oct 10 2008, 20:34

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Post n°61

Re: Math

Post by Meika-Chan Fri Oct 10 2008, 20:34

amaterasu wrote:well check the formula and see if it is right

2x^2+4x > x^2-x-6
so 2(3)^2+4(3) > (3)^2-2-6
so 36+12 > 9-8
so 48 > 1

so you are right

Okay :D Thankies~

by **tsuki_uchiha** Fri Oct 10 2008, 22:55

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Post n°62

Re: Math

Post by tsuki_uchiha Fri Oct 10 2008, 22:55

a-2+3= -2

please help i suck at math Crying

by **amaterasu** Fri Oct 10 2008, 23:15

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Post n°63

Re: Math

Post by amaterasu Fri Oct 10 2008, 23:15

tsuki_uchiha wrote:a-2+3= -2

please help i suck at math

well

a-2 + 3 = -2

add 2 to each side

so
a + 3 = 0

than minus 3 to each side

so a = -3

by **tsuki_uchiha** Fri Oct 10 2008, 23:40

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Post n°64

Re: Math

Post by tsuki_uchiha Fri Oct 10 2008, 23:40

amaterasu wrote:

tsuki_uchiha wrote:a-2+3= -2

please help i suck at math

well

a-2 + 3 = -2

add 2 to each side

so
a + 3 = 0

than minus 3 to each side

so a = -3

thanks, 8(8x-7)-2(-6x+2)

by **Claud-kun** Sun Oct 12 2008, 05:09

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Post n°65

Re: Math

Post by Claud-kun Sun Oct 12 2008, 05:09

You missed the equal in there.

by **King_Of_Blades** Sun Oct 12 2008, 11:42

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Post n°66

Re: Math

Post by King_Of_Blades Sun Oct 12 2008, 11:42

im very goood with some algerbra lol

by **amaterasu** Sun Oct 12 2008, 16:38

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Post n°67

Re: Math

Post by amaterasu Sun Oct 12 2008, 16:38

tsuki_uchiha wrote:

amaterasu wrote:

tsuki_uchiha wrote:a-2+3= -2

please help i suck at math

well

a-2 + 3 = -2

add 2 to each side

so
a + 3 = 0

than minus 3 to each side

so a = -3

thanks, 8(8x-7)-2(-6x+2)

Your missing something there aren't you?

by **King_Of_Blades** Wed Oct 15 2008, 15:44

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Post n°68

Re: Math

Post by King_Of_Blades Wed Oct 15 2008, 15:44

yup i a genius let me guess is it a =

by **PeinQAkatsuki** Wed Nov 19 2008, 21:35

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Post n°69

Re: Math

Post by PeinQAkatsuki Wed Nov 19 2008, 21:35

Okay, more mathematical needs:

4z+b=2z+c, for z.

So I'm supposed to simplify as far as I can to figure out what z is. It's impossible to find the real answer, so I think, so I have to find the closest I can come (with an equation btw).

So, for the 4z, so I add or subtract it?

by **theBOSS.** Wed Nov 19 2008, 21:39

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Post n°70

Re: Math

Post by theBOSS. Wed Nov 19 2008, 21:39

4z+b=2z+c
Subtract 2z on both sides:
2z+b=c
Isolate 2z by subtracting b:
2z=c-b
Now isolate z by dividing the coefficient or whatever it's called:
z=(c-b)/2

by **PeinQAkatsuki** Wed Nov 19 2008, 21:44

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Post n°71

Re: Math

Post by PeinQAkatsuki Wed Nov 19 2008, 21:44

Okay... so I subtract the b from the c.... OH I GET IT! Thanks Deathy!

by **PeinQAkatsuki** Wed Nov 19 2008, 21:48

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Post n°72

Re: Math

Post by PeinQAkatsuki Wed Nov 19 2008, 21:48

Okay, so you can't solve

p=a(b+c), for a

can you?

by **quater** Wed Nov 19 2008, 21:50

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Post n°73

Re: Math

Post by quater Wed Nov 19 2008, 21:50

I think you can.

Divide both sides by (B+C) so that you have P/(B+C) = A?

Am I right? I mean, (b+c) is like a variable being multiplied by another?

I could be way off my knocker. Learning anti-derivatives does that to me.

by **PeinQAkatsuki** Wed Nov 19 2008, 21:52

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Post n°74

Re: Math

Post by PeinQAkatsuki Wed Nov 19 2008, 21:52

That's what I thought, and it seems logical.

by **theBOSS.** Wed Nov 19 2008, 22:17

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Post n°75

Re: Math

Post by theBOSS. Wed Nov 19 2008, 22:17

ILURVEMATH.
well compared to ush, it's heaven

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