Math

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First Math Problem!

I'm doing some Algebra right now but don't know what to do:

Find b:

ab-3a=5

I know you divide the whole thing by a but then what?

find b


first you add 3a to each side so it ends up

ab=5+3a

than divide each side by a so it is
b=5+2a


basically that seems to be the fartest you can go

amaterasu wrote:find b


first you add 3a to each side so it ends up

ab=5+3a

than divide each side by a so it is
b=5+2a


basically that seems to be the fartest you can go

When you said divide each side by a, I lost you. Sort of.

Isn't it...

b=5/a+3 ?

I am super lost.

Titaniumxvx wrote:

amaterasu wrote:find b


first you add 3a to each side so it ends up

ab=5+3a

than divide each side by a so it is
b=5+2a


basically that seems to be the fartest you can go

When you said divide each side by a, I lost you. Sort of.

Isn't it...

b=5/a+3 ?

I am super lost.

Yes, it would be. He must have made a mistake.

Titaniumxvx wrote:First Math Problem!

I'm doing some Algebra right now but don't know what to do:

Find b:

ab-3a=5

I know you divide the whole thing by a but then what?

I have no clue what ama did, so this is what I would do o.o

(ab-3a)/a=5/a

Which simplifies to b-3=5/a

And then you add 3 to each end

b=5\a + 3

which means ama messed up somewhere ._.

Titaniumxvx wrote:

amaterasu wrote:find b


first you add 3a to each side so it ends up

ab=5+3a

than divide each side by a so it is
b=5+2a


basically that seems to be the fartest you can go

When you said divide each side by a, I lost you. Sort of.

Isn't it...

b=5/a+3 ?

I am super lost.

no, you have ab=5+3a

you want to get the b alone
so divide each side by a will isolate the b

on the other side you have 5+3a. When you divide that by a you will get 5+2a. The five won't get affected, but the 3a will go down to 2a

amaterasu wrote:

Titaniumxvx wrote:

amaterasu wrote:find b


first you add 3a to each side so it ends up

ab=5+3a

than divide each side by a so it is
b=5+2a


basically that seems to be the fartest you can go

When you said divide each side by a, I lost you. Sort of.

Isn't it...

b=5/a+3 ?

I am super lost.

no, you have ab=5+3a

you want to get the b alone
so divide each side by a will isolate the b

on the other side you have 5+3a. When you divide that by a you will get 5+2a. The five won't get affected, but the 3a will go down to 2a

EEEEHHHHHHHHHHHHH!

Wrong, 'materasu. It doesn't work that way. You have to divide all terms by the a. And if you have a over a, it cancels each other out so you get 3.

how on earth did you get into the advanced math course?

Amaterasu, Aichu, and Meika are confusing me!

I got b=5/a+3? I just have to know if it is right since you all disagree or at least Terasu

ab-3a=5

add 3a to both sides

so now, its:

ab=5+3a

Now i think you subtract a from both. i dont remember much algebra....

b=5+2a

same as ama said.

Titaniumxvx wrote:Amaterasu, Aichu, and Meika are confusing me!

I got b=5/a+3? I just have to know if it is right since you all disagree or at least Terasu

That's right.

it is? i must be really sick

Uh oh, it's two against two. Poor titan!

Meika-Chan wrote:

Titaniumxvx wrote:Amaterasu, Aichu, and Meika are confusing me!

I got b=5/a+3? I just have to know if it is right since you all disagree or at least Terasu

That's right.

NG just got Terasu's answer, too!

But you, me, and Aichu have the same answer. Oh, Geez

Titaniumxvx wrote:Amaterasu, Aichu, and Meika are confusing me!

I got b=5/a+3? I just have to know if it is right since you all disagree or at least Terasu

you don't separate the 3a into 3+a

what are you thining?


3+a is totally different than 3a

Titaniumxvx wrote:

Meika-Chan wrote:

Titaniumxvx wrote:Amaterasu, Aichu, and Meika are confusing me!

I got b=5/a+3? I just have to know if it is right since you all disagree or at least Terasu

That's right.

NG just got Terasu's answer, too!

But you, me, and Aichu have the same answer. Oh, Geez

thats cuz 3a is 3 mutiplied by a not 3 + a.....

i really dont remember much algebra ^^;;

amaterasu wrote:

Titaniumxvx wrote:Amaterasu, Aichu, and Meika are confusing me!

I got b=5/a+3? I just have to know if it is right since you all disagree or at least Terasu

you don't separate the 3a into 3+a

what are you thining?


3+a is totally different than 3a

What? Where are you getting 3+a from?

ab-3a=5

Since -3a is a term, you can move it to the other side of the equation through addition. It's like having 2x-5=5y-3: You can move the terms to either side.

So we have ab=5+3a

Now, we want to isolate b. Since the value of a is multiplied by the value of b, if you divide b by the value of a you will isolate b, but you must do the same to all terms on both sides of the equations. And so, you get five over a, and by dividing a from 3 a, which is basically the value three multiplied by a, the a will be canceled out from this term.

b=5/a+3

Easy peasy lemon squeezy.

Aichu wrote:ab-3a=5

Since -3a is a term, you can move it to the other side of the equation through addition. It's like having 2x-5=5y-3: You can move the terms to either side.

So we have ab=5+3a

Now, we want to isolate b. Since the value of a is multiplied by the value of b, if you divide b by the value of a you will isolate b, but you must do the same to all terms on both sides of the equations. And so, you get five over a, and by dividing a from 3 a, which is basically the value three multiplied by a, the a will be canceled out from this term.

b=5/a+3

Easy peasy lemon squeezy.

no because you have 5+3a

divide 3a by a doesn't give you 3+a it gives you 2a

*sigh*

if you have 6(5), and you divide the term by five, what are you going to get ama?

Siiiiiix. You will get six.

Unless you can prove me wrong, in which case I will look like a complete idiot. But that's perfectly okay.

Aichu wrote:*sigh*

if you have 6(5), and you divide the term by five, what are you going to get ama?

ah!

your right, I was malthinking

by bad my bad

Amaterasu!

Thanks, Aichu Pichu

amaterasu wrote:

Aichu wrote:*sigh*

if you have 6(5), and you divide the term by five, what are you going to get ama?

ah!

your right, I was malthinking

by bad my bad

Bingo! You win a funky sticker.

Aichu wrote:

amaterasu wrote:

Aichu wrote:*sigh*

if you have 6(5), and you divide the term by five, what are you going to get ama?

ah!

your right, I was malthinking

by bad my bad

Bingo! You win a funky sticker.

I was thinking of substracting



so
ab-3a=5
ab=5+3a
b=5+3a/a
b=5+3
_____
|b=8|